Rat and poison bottle puzzle:
Puzzle: There 8 bottles and one of them have poison. How may minimum rats you want to find out in which bottol have poison. Condition is that you need to feed all rats at same time and only once?
Answer: You need to mix the bottles in different combinations and then find out on the basis of which rat is dead.
(2) power 3 = 8 so you need minimum 3 rats to find the poisonous bottle.
lets have 3 rats A, B , C and you have to mix 8 bottles in such way that you get unique mixture.
we have bottles b1, b2, b3, b4, b5, b6, b7, b8
lets mix and make 3 mixtures:
lets represent every bottle in binary:
b8: leave it.
mix 1: which contains 1 at right most - b1,b3, b5, b7
mix 2: middle onc - b2, b3, b6, b7
mix 3: leftmost one: b4, b5, b6, b7
now give mix 1 to rat A
mix 2 to rat B
and mix 3 to rat C
if all three rats die it means b7 is common in all three mixture so b7 have poison
if non will die it means b8 have poison
if rat A only die it means b1 have poison
if rat A, B die it means b3 have poison etc